Let the tangent to the circle $C _{1}: x^{2}+y^{2}=2$ at the point $M (-1,1)$ intersect the circle $C _{2}$ : $( x -3)^{2}+(y-2)^{2}=5$, at two distinct points $A$ and $B$. If the tangents to $C _{2}$ at the points $A$ and $B$ intersect at $N$, then the area of the triangle $ANB$ is equal to

  • [JEE MAIN 2022]
  • A

    $\frac{1}{2}$

  • B

    $\frac{2}{3}$

  • C

    $\frac{1}{6}$

  • D

    $\frac{5}{3}$

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