Write the first five terms of the sequences whose $n^{t h}$ term is $a_{n}=n(n+2)$
Write the first five terms of the sequences whose $n^{t h}$ term is $a_{n}=n(n+2)$
$a_{n}=n(n+2)$
Substituting $n=1,2,3,4$ and $5,$ we obtain
$a_{1}=1(1+2)=3$
$a_{2}=2(2+2)=8$
$a_{3}=3(3+2)=15$
$a_{4}=4(4+2)=24$
$a_{5}=5(5+2)=35$
Therefore, the required terms are $3,8,15,24$ and $35 .$
Similar Questions
If $19^{th}$ terms of non -zero $A.P.$ is zero, then its ($49^{th}$ term) : ($29^{th}$ term) is
If $19^{th}$ terms of non -zero $A.P.$ is zero, then its ($49^{th}$ term) : ($29^{th}$ term) is
- [JEE MAIN 2019]
If ${S_n}$ denotes the sum of $n$ terms of an arithmetic progression, then the value of $({S_{2n}} - {S_n})$ is equal to
If ${S_n}$ denotes the sum of $n$ terms of an arithmetic progression, then the value of $({S_{2n}} - {S_n})$ is equal to
If $\log _{3} 2, \log _{3}\left(2^{x}-5\right), \log _{3}\left(2^{x}-\frac{7}{2}\right)$ are in an arithmetic progression, then the value of $x$ is equal to $.....$
If $\log _{3} 2, \log _{3}\left(2^{x}-5\right), \log _{3}\left(2^{x}-\frac{7}{2}\right)$ are in an arithmetic progression, then the value of $x$ is equal to $.....$
- [JEE MAIN 2021]
If $\log 2,\;\log ({2^n} - 1)$ and $\log ({2^n} + 3)$ are in $A.P.$, then $n =$
If $\log 2,\;\log ({2^n} - 1)$ and $\log ({2^n} + 3)$ are in $A.P.$, then $n =$
Suppose that the number of terms in an $A.P.$ is $2 k$, $k \in N$. If the sum of all odd terms of the $A.P.$ is $40 ,$ the sum of all even terms is $55$ and the last term of the $A.P.$ exceeds the first term by $27$ , then $k$ is equal to
- [JEE MAIN 2025]