If the variable line 3 x+4 y=alpha lies betwe | vedclass

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Question

Both centres should lie on either side of the line as well as line can be tangent to circle.

$(3+4-\alpha) \cdot(27+4-\alpha)\,<\,0$

$(7-\alp

Vedclass · Accepted Answer

$165$

Vedclass · Answer

Both centres should lie on either side of the line as well as line can be tangent to circle.

$(3+4-\alpha) \cdot(27+4-\alpha)\,<\,0$

$(7-\alpha) \cdot(31-\alpha)<0 \Rightarrow \alpha \in(7,31) \quad \ldots(1)$

$d_{1}=	ext { distance of }(1,1) 	ext { from line }$

$d_{2}=	ext { distance of }(9,1) 	ext { from line }$

$d_{1} \geq r_{1} \Rightarrow \frac{|7-\alpha|}{5} 1 \Rightarrow \alpha \in(-\infty, 2] \cup[12, \infty) \ldots(2)$

$d_{2} \geq r_{2} \Rightarrow \frac{|31-\alpha|}{5} \geq 2 \Rightarrow \alpha \in(-\infty, 21] \cup[41, \infty)\ldots(3)$

$(1) \cap(2) \cap(3) \Rightarrow \alpha \in[12,21]$

Sum of integers $=165$

If the variable line $3 x+4 y=\alpha$ lies between the two circles $(x-1)^{2}+(y-1)^{2}=1$ and $(x-9)^{2}+(y-1)^{2}=4$ without intercepting a chord on either circle, then the sum of all the integral values of $\alpha$ is .... .

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