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13.Statistics
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If the variance of the first $n$ natural numbers is $10$ and the variance of the first m even natural numbers is $16$, then $m + n$ is equal to
A
$16$
B
$18$
C
$24$
D
$22$
(JEE MAIN-2020)
Solution
Variance of first 'n' natural numbers $=\frac{\mathrm{n}^{2}-1}{12}=10$
$\Rightarrow n=11$
and variance of first 'm' even natural numbers
$=4\left(\frac{\mathrm{m}^{2}-1}{12}\right) \Rightarrow \frac{\mathrm{m}^{2}-1}{3}=16 \Rightarrow \mathrm{m}=7$
$m+n=18$
Standard 11
Mathematics
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