- Home
- Standard 11
- Mathematics
8. Sequences and Series
medium
If twice the $11^{th}$ term of an $A.P.$ is equal to $7$ times of its $21^{st}$ term, then its $25^{th}$ term is equal to
A
$24$
B
$120$
C
$0$
D
None of these
Solution
(c) Let the first term of $A.P. $ is a and common difference is $d$.
$11^{th}$ term of $A.P. =$ $a + 10d$
$21^{st}$ term of $A.P. = a+ 20d$
$2(a + 10d) = 7(a + 20d)$
==> $2a + 20d = 7a + 140d$
$5a + 120d = 0$
==> $a + 24d = 0$
Hence $25^{th}$ term is $0.$
Standard 11
Mathematics