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14.Probability
hard
If two different numbers are taken from the set $\left\{ {0,1,2,3, \ldots ,10} \right\}$, then the probability that their sum as well as absolute difference are both multiple of $4$, is
A
$\frac{7}{{55}}$
B
$\frac{6}{{55}}$
C
$\frac{{12}}{{55}}$
D
$\frac{{14}}{{55}}$
(JEE MAIN-2017)
Solution
Let $A \equiv \{ 0,1,2,3,4, \ldots ..,10\} $
${\rm{n}}({\rm{S}}) = {\,^{11}}{{\rm{C}}_2} = 55$ where $'S'$ denotes sample space
Let $\mathrm{E}$ be the given event
$\therefore {\rm{E}} \equiv \{ (0,4),(0,8),(2,6),(2,10),(4,8),(6,10)\} $
$\Rightarrow \mathrm{n}(\mathrm{E})=6$
$\therefore P(E)=\frac{n(E)}{n(S)}=\frac{6}{55}$
Standard 11
Mathematics
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