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In an experiment with $15$ observations on $x$, the following results were available $\sum {x^2} = 2830$, $\sum x = 170$. On observation that was $20$ was found to be wrong and was replaced by the correct value $30$. Then the corrected variance is..
$78$
$188.66$
$177.33$
$8.33$
Solution
(a) $\sum x = 170$, $\sum {x^2} = 2830$
Increase in $\sum x = 10$, then $\sum x' = 170 + 10 = 180$
Increase in $\sum {x^2} = 900 – 400 = 500$, then
$\sum {x'^2} = 2830 + 500 = 3330$
Variance $ = \frac{1}{n}\sum {x'^2} – {\left( {\frac{{\sum x'}}{n}} \right)^2}$
$ = \frac{{3330}}{{15}} – {\left( {\frac{{180}}{{15}}} \right)^2} = 222 – 144 = 78$.
Similar Questions
What is the standard deviation of the following series
class |
0-10 |
10-20 |
20-30 |
30-40 |
Freq |
1 |
3 |
4 |
2 |
Let $\mu$ be the mean and $\sigma$ be the standard deviation of the distribution
$X_i$ | $0$ | $1$ | $2$ | $3$ | $4$ | $5$ |
$f_i$ | $k+2$ | $2k$ | $K^{2}-1$ | $K^{2}-1$ | $K^{2}-1$ | $k-3$ |
where $\sum f_i=62$. if $[x]$ denotes the greatest integer $\leq x$, then $\left[\mu^2+\sigma^2\right]$ is equal $………$.