In an experiment with 15 observations on x, t | vedclass

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Question

(a) $\sum x = 170$, $\sum {x^2} = 2830$

Increase in $\sum x = 10$, then $\sum x' = 170 + 10 = 180$

Increase in $\sum {x^2} = 900 - 400 = 500

Vedclass · Accepted Answer

$78$

Vedclass · Answer

(a) $\sum x = 170$, $\sum {x^2} = 2830$

Increase in $\sum x = 10$, then $\sum x' = 170 + 10 = 180$

Increase in $\sum {x^2} = 900 - 400 = 500$, then

$\sum {x'^2} = 2830 + 500 = 3330$

Variance $ = \frac{1}{n}\sum {x'^2} - {\left( {\frac{{\sum x'}}{n}} \right)^2}$

$ = \frac{{3330}}{{15}} - {\left( {\frac{{180}}{{15}}} \right)^2} = 222 - 144 = 78$.

Variate $( x )$	$x _{1}$	$x _{1}$	$x _{3} \ldots \ldots x _{15}$
Frequency $(f)$	$f _{1}$	$f _{1}$	$f _{3} \ldots f _{15}$

In an experiment with $15$ observations on $x$, the following results were available $\sum {x^2} = 2830$, $\sum x = 170$. On observation that was $20$ was found to be wrong and was replaced by the correct value $30$. Then the corrected variance is..

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