In countries like USA and Canada, temperature is measured in Fahrenheit, whereas in countries like India, it is measured in Celsius. Here is a linear equation that converts Fahrenheit to Celsius :
$F =\left(\frac{9}{5}\right) C +32$
$(i)$ Draw the graph of the linear equation above using Celsius for $x$ - axis and Fahrenheit for $y$ - axis.
$(ii)$ If the temperature is $30\,^oC$, what is the temperature in Fahrenheit ?
$(iii)$ If the temperature is $95\,^oF$, what is the temperature in Celsius ?
$(iv)$ If the temperature is $0\,^oC$ , what is the temperature in Fahrenheit and if the temperature is $0\,^oF$ , what is the temperature in Celsius ?
$(v)$ Is there a temperature which is numerically the same in both Fahrenheit and Celsius ? If yes, find it.
In countries like USA and Canada, temperature is measured in Fahrenheit, whereas in countries like India, it is measured in Celsius. Here is a linear equation that converts Fahrenheit to Celsius :
$F =\left(\frac{9}{5}\right) C +32$
$(i)$ Draw the graph of the linear equation above using Celsius for $x$ - axis and Fahrenheit for $y$ - axis.
$(ii)$ If the temperature is $30\,^oC$, what is the temperature in Fahrenheit ?
$(iii)$ If the temperature is $95\,^oF$, what is the temperature in Celsius ?
$(iv)$ If the temperature is $0\,^oC$ , what is the temperature in Fahrenheit and if the temperature is $0\,^oF$ , what is the temperature in Celsius ?
$(v)$ Is there a temperature which is numerically the same in both Fahrenheit and Celsius ? If yes, find it.
$(i)$ We have $F =\left(\frac{9}{5}\right) C +32$
When $C=0$, $F=\left(\frac{9}{5}\right) \times 0+32=32$
When $C=-\,15$, $F =\frac{9}{5}(-15)+32=-27+32=5$
When $C=-\,10$, $F=\frac{9}{5}(-10)+32=9(-2)+32=14$
We have the following table:
| $C$ | $0$ | $-15$ | $-10$ |
| $F$ | $32$ | $5$ | $14$ |
Plot the ordered pairs $(0,\,32)$, $(-\,15,\,5)$ and $(-\,10,\,14)$ on a graph paper. Joining these points we get a straight line $AB$.
$(ii)$ From the graph, we have
$86\,^oF$ corresponds to $30\,^oC$
$(iii)$ From the graph, we have
$95\,^oF =35\,^oC $
$(iv)$ From the graph, we have
$0\,^oC =32\,^oF $
and $0\,^oF =17.8\,^oC $
$(v)$ Yes, from the graph, we have
$40\,^oF =-40\,^oC $
Similar Questions
Check the solutions of the equation $x -2y = 4$ and which are not : $(0,\,2)$
Check the solutions of the equation $x -2y = 4$ and which are not : $(0,\,2)$
Write four solutions for equations : $x=4 y$
Write four solutions for equations : $x=4 y$
Check the solutions of the equation $x -2y = 4$ and which are not : $(2,\,0)$
Check the solutions of the equation $x -2y = 4$ and which are not : $(2,\,0)$
Express the following linear equations in the form $ax + by + c = 0$ and indicate the values of $a$, $b$ and $c$ in each case : $x-\frac{y}{5}-10=0$
Express the following linear equations in the form $ax + by + c = 0$ and indicate the values of $a$, $b$ and $c$ in each case : $x-\frac{y}{5}-10=0$
The cost of a notebook is twice the cost of a pen. Write a linear equation in two variables to represent this statement.
(Take the cost of a notebook to be $\rm {Rs.}$ $x$ and that of a pen to be $\rm {Rs.}$ $y$).
The cost of a notebook is twice the cost of a pen. Write a linear equation in two variables to represent this statement.
(Take the cost of a notebook to be $\rm {Rs.}$ $x$ and that of a pen to be $\rm {Rs.}$ $y$).