In order to make the effective acceleration d | vedclass

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Question

(b)$g' = g - {\omega ^2}R{\cos ^2}\lambda \,$

For weightlessness at equator $\lambda = 0$ and $g' = 0$

$0 = g - {\omega ^2}R$

$\omega

Vedclass · Accepted Answer

$\frac{1}{{800}}rad\,se{c^{ - 1}}$

Vedclass · Answer

(b)$g' = g - {\omega ^2}R{\cos ^2}\lambda \,$

For weightlessness at equator $\lambda = 0$ and $g' = 0$

$0 = g - {\omega ^2}R$

$\omega = \sqrt {\frac{g}{R}} = \frac{1}{{800}}\;\frac{{rad}}{s}$

In order to make the effective acceleration due to gravity equal to zero at the equator, the angular velocity of rotation of the earth about its axis should be $(g = 10\,m{s^{ - 2}}$ and radius of earth is $6400 \,kms)$

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