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7.Binomial Theorem
easy
${\left( {x + \frac{2}{{{x^2}}}} \right)^{15}}$ ના વિસ્તરણમાં અચળપદ મેળવો.
A
$^{15}{C_6}{2^6}$
B
$^{15}{C_5}{2^5}$
C
$^{15}{C_4}{2^4}$
D
$^{15}{C_8}{2^8}$
Solution
(b) $(15 – r)(1) + r( – 2) = 0\,\, \Rightarrow 15 – 3r = 0 \Rightarrow r = 5$
Thus term independent of $x$ is
$ = {\,^{15}}{C_5}{(1)^{10}}{(2)^5} = {\,^{15}}{C_5}{2^5}$.
Standard 11
Mathematics
