Let a_n be a sequence such that a_1 = 5 and a | vedclass

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Question

$\begin{array}{*{20}{c}}
{{a_{n + 1}} - {a_n} = n - 2}\
{{a_{51}} - {a_{50}} = 48}\
{{a_{50}} - {a_{49}} = 47}\
 \vdots \
{{a_3} - {a_2}

Vedclass · Accepted Answer

$1180$

Vedclass · Answer

$\begin{array}{*{20}{c}}
{{a_{n + 1}} - {a_n} = n - 2}\
{{a_{51}} - {a_{50}} = 48}\
{{a_{50}} - {a_{49}} = 47}\
 \vdots \
{{a_3} - {a_2} = 0}\
{{a_2} - {a_1} =  - 1}
\end{array}$

${a_{51}} - {a_1} =  - 1 + 0 + 1 + 2 + ...... + 48$

${a_{51}} - 5 = 1175 \Rightarrow {a_{51}} = 1180$

Let $a_n$ be a sequence such that $a_1 = 5$ and $a_{n+1} = a_n + (n -2)$ for all $n \in N$, then $a_{51}$ is

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