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1.Relation and Function
normal
Let $f(x) = cos(\sqrt P \,x),$ where $P = [\lambda], ([.]$ is $G.I.F.)$ If the period of $f(x)$ is $\pi$. then
A
$\lambda \, \in [4, 5]$
B
$\lambda \, \in [1, 2)$
C
$\lambda \, \in [4, 5)$
D
$\lambda$ does not exist
Solution
$\frac{2 \pi}{\sqrt{\mathrm{p}}}=\pi$
$\sqrt{\mathrm{p}}=2$
$\mathrm{P}=4$
$[\lambda]=4$$\quad$ Given $\mathrm{p}=[\lambda]$
$\lambda \in[4.5)$
Standard 12
Mathematics