Let P = left{ {theta :sin ,theta - cos | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\sin \,	heta \, - \,\cos \,	heta \,\, = \,\,\sqrt 2 \,\cos \,	heta $

$ \Rightarrow \,\sin \,	heta \, = \,\cos \,	heta \,\, + \,\,\sqrt 2 \,\c

Vedclass · Accepted Answer

$P = Q$

Vedclass · Answer

$\sin \,	heta \, - \,\cos \,	heta \,\, = \,\,\sqrt 2 \,\cos \,	heta $

$ \Rightarrow \,\sin \,	heta \, = \,\cos \,	heta \,\, + \,\,\sqrt 2 \,\cos \,	heta $

$ = \,(\sqrt 2 \, + \,1)\cos \,	heta \, = \,\left( {\frac{{2\, - \,1}}{{\sqrt 2 \, - \,1}}} ight)\,\cos \,	heta $

$ \Rightarrow \,(\sqrt 2 \, - \,1)\sin \,	heta  = \,\cos \,	heta $

$ \Rightarrow \,\sin \,	heta \, + \,\cos \,	heta \,\, = \,\,\sqrt 2 \,\cos \,	heta $

$	herefore \,\,P\, = \,Q$

Let $P = \left\{ {\theta :\sin \,\theta - \cos \,\theta = \sqrt 2 \,\cos \,\theta } \right\}$ and $Q = \left\{ {\theta :\sin \,\theta + \cos \,\theta = \sqrt {2\,} \sin \,\theta } \right\}$ be two sets. Then

Similar Questions

$\sin 6\theta + \sin 4\theta + \sin 2\theta = 0,$ then $\theta = $

All possible values of $\theta \in[0,2 \pi]$ for which $\sin 2 \theta+\tan 2 \theta>0$ lie in

The general value of $\theta $satisfying the equation $2{\sin ^2}\theta - 3\sin \theta - 2 = 0$ is

If $2{\cos ^2}x + 3\sin x - 3 = 0,\,\,0 \le x \le {180^o}$, then $x =$

If $\sin 2\theta = \cos \theta ,\,\,0 < \theta < \pi $, then the possible values of $\theta $ are