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4-2.Quadratic Equations and Inequations
hard
Let $\lambda \in R$ and let the equation $E$ be $| x |^2-2| x |+|\lambda-3|=0$. Then the largest element in the set $S =$ $\{ x +\lambda: x$ is an integer solution of $E \}$ is $..........$
A
$4$
B
$3$
C
$5$
D
$2$
(JEE MAIN-2023)
Solution
$| x |^2-2| x |+|\lambda-3|=0$
$| x |^2-2| x |+|\lambda-3|-1=0$
$(| x |-1)^2+|\lambda-3|=1$
At $\lambda=3, x =0$ and 2 ,
at $\lambda=4$ or 2 , then
$x =1 \text { or }-1$
So maximum value of $x+\lambda=5$
Standard 11
Mathematics