- Home
- Standard 12
- Mathematics
Let $R$ be a relation on $R$, given by $R=\{(a, b): 3 a-3 b+\sqrt{7}$ is an irrational number $\}$. Then $R$ is
Reflexive but neither symmetric nor transitive
Reflexive and transitive but not symmetric
Reflexive and symmetric but not transitive
An equivalence relation
Solution
Check for reflexivity:
As $3(a-a)+\sqrt{7}=\sqrt{7}$ which belongs to relation so relation is reflexive
Check for symmetric:
Take $a=\frac{\sqrt{7}}{3}, b=0$
Now $(a, b) \in R$ but $(b, a) \notin R$
As $3(b-a)+\sqrt{7}=0$ which is rational so relation is not symmetric.
Check for Transitivity:
Take $(a, b)$ as $\left(\frac{\sqrt{7}}{3}, 1\right)$
$\&(b, c)$ as $\left(1, \frac{2 \sqrt{7}}{3}\right)$
So now $( a , b ) \in R \&( b , c ) \in R$ but $( a , c ) \notin R$ which means relation is not transitive