1.Relation and Function
hard

Let $R$ be a relation on $R$, given by $R=\{(a, b): 3 a-3 b+\sqrt{7}$ is an irrational number $\}$. Then $R$ is

A

Reflexive but neither symmetric nor transitive

B

Reflexive and transitive but not symmetric

C

Reflexive and symmetric but not transitive

D

An equivalence relation

(JEE MAIN-2023)

Solution

Check for reflexivity:

As $3(a-a)+\sqrt{7}=\sqrt{7}$ which belongs to relation so relation is reflexive

Check for symmetric:

Take $a=\frac{\sqrt{7}}{3}, b=0$

Now $(a, b) \in R$ but $(b, a) \notin R$

As $3(b-a)+\sqrt{7}=0$ which is rational so relation is not symmetric.

Check for Transitivity:

Take $(a, b)$ as $\left(\frac{\sqrt{7}}{3}, 1\right)$

$\&(b, c)$ as $\left(1, \frac{2 \sqrt{7}}{3}\right)$

So now $( a , b ) \in R \&( b , c ) \in R$ but $( a , c ) \notin R$ which means relation is not transitive

Standard 12
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.