Let Sₙ denote sum of first n terms of an arithmetic progression. If mathrm{S}

English

Gujarati

Hindi

8. Sequences and Series

hard

Let $S_n$ denote the sum of the first $n$ terms of an arithmetic progression. If $\mathrm{S}_{10}=390$ and the ratio of the tenth and the fifth terms is $15: 7$, then $S_{15}-S_5$ is equal to:

$800$

$890$

$790$

$690$

(JEE MAIN-2024)

Solution

$ \mathrm{S}_{10}=390 $

$ \frac{10}{2}[2 \mathrm{a}+(10-1) \mathrm{d}]=390 $

$ \Rightarrow 2 \mathrm{a}+9 \mathrm{~d}=78 $ $……(1)$

$ \frac{\mathrm{t}_{10}}{\mathrm{t}_5}=\frac{15}{7} \Rightarrow \frac{\mathrm{a}+9 \mathrm{~d}}{\mathrm{a}+4 \mathrm{~d}}=\frac{15}{7} \Rightarrow 8 \mathrm{a}=3 \mathrm{~d} $ $……(2)$

$ \text { From }(1) \&(2) \quad \mathrm{a}=3 \& \mathrm{~d}=8 $

$ \mathrm{~S}_{15}-\mathrm{S}_5=\frac{15}{2}(6+14 \times 8)-\frac{5}{2}(6+4 \times 8) $

$ =\frac{15 \times 118-5 \times 38}{2}=790$

Standard 11

Mathematics

Let $a_1, a_2, a_3, \ldots, a_{100}$ be an arithmetic progression with $a_1=3$ and $S_p=\sum_{i=1}^p a_i, 1 \leq p \leq 100$. For any integer $n$ with $1 \leq n \leq 20$, let $m=5 n$. If $\frac{S_{m m}}{S_n}$ does not depend on $n$, then $a_2$ is

normal

(IIT-2011)

The sums of $n$ terms of two arithmatic series are in the ratio $2n + 3:6n + 5$, then the ratio of their ${13^{th}}$ terms is

medium

In an $A.P.,$ if $p^{\text {th }}$ term is $\frac{1}{q}$ and $q^{\text {th }}$ term is $\frac{1}{p},$ prove that the sum of first $p q$ terms is $\frac{1}{2}(p q+1),$ where $p \neq q$

hard

Find the $9^{\text {th }}$ term in the following sequence whose $n^{\text {th }}$ term is $a_{n}=(-1)^{n-1} n^{3}$

easy

A number is the reciprocal of the other. If the arithmetic mean of the two numbers be $\frac{{13}}{{12}}$, then the numbers are