Let $z$be a purely imaginary number such that ${\mathop{\rm Im}\nolimits} \,(z) > 0$. Then $arg(z)$ is equal to
Let $z$be a purely imaginary number such that ${\mathop{\rm Im}\nolimits} \,(z) > 0$. Then $arg(z)$ is equal to
- A
$\pi $
- B
$\frac{\pi }{2}$
- C
$0$
- D
$ - \frac{\pi }{2}$
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