Let z be a complex number. Then angle between vectors z and - iz is

English

Gujarati

Hindi

4-1.Complex numbers

easy

Let $z$ be a complex number. Then the angle between vectors $z$ and $ - iz$ is

A

$\pi $

B

$0$

C

$ - \frac{\pi }{2}$

D

None of these

Solution

(c) Since the multiplication of a complex number by $ – i$ rotates through it by a right angle in negative (clockwise) direction.

Standard 11

Mathematics

Share

Similar Questions

If $z$ is a complex number such that ${z^2} = {(\bar z)^2},$ then

medium

If ${z_1},{z_2}$ and ${z_3},{z_4}$ are two pairs of conjugate complex numbers, then $arg\left( {\frac{{{z_1}}}{{{z_4}}}} \right) + arg\left( {\frac{{{z_2}}}{{{z_3}}}} \right)$ equals

medium

The value of $|z – 5|$if $z = x + iy$, is

normal

If $(3 + i)z = (3 – i)\bar z,$then complex number $z$ is

easy

If $\frac{3+i \sin \theta}{4-i \cos \theta}, \theta \in[0,2 \pi],$ is a real number, then an argument of $\sin \theta+\mathrm{i} \cos \theta$ is

hard

(JEE MAIN-2020)