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8. Sequences and Series
easy
Let ${S_n}$ denotes the sum of $n$ terms of an $A.P.$ If ${S_{2n}} = 3{S_n}$, then ratio $\frac{{{S_{3n}}}}{{{S_n}}} = $
A
$4$
B
$6$
C
$8$
D
$10$
Solution
(b) ${S_{2n}} = 3{S_n}$
$ \Rightarrow $ $\frac{{2n}}{2}\{ 2a + (2n – 1)d\} = 3\;.\;\frac{n}{2}\{ 2a + (n – 1)d\} $
$ \Rightarrow $ $2a = (n + 1)d$
Put $2a = (n + 1)d$ in $\frac{{{S_{3n}}}}{{{S_n}}}$,
we get its value $6$.
Standard 11
Mathematics