Let $0 < x < \frac{\pi }{4}.$ Then $\sec 2x - \tan 2x = $
Let $0 < x < \frac{\pi }{4}.$ Then $\sec 2x - \tan 2x = $
- [IIT 1994]
- A
$\tan \left( {x - \frac{\pi }{4}} \right)$
- B
$\tan \left( {\frac{\pi }{4} - x} \right)$
- C
$\tan \left( {x + \frac{\pi }{4}} \right)$
- D
${\tan ^2}\left( {x + \frac{\pi }{4}} \right)$
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- [IIT 1984]
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