Let $PQ$ and $RS$ be tangents at the extremeties of the diameter $PR$ of a circle of radius $r$. If $PS$ and $RQ$ intersect at a point $X$ on the circumference of the circle, then $2r$ equals
Let $PQ$ and $RS$ be tangents at the extremeties of the diameter $PR$ of a circle of radius $r$. If $PS$ and $RQ$ intersect at a point $X$ on the circumference of the circle, then $2r$ equals
- [IIT 2001]
- A
$\sqrt {PQ.RS} $
- B
$\frac{{PQ + RS}}{2}$
- C
$\frac{{2PQ.\,\,RS}}{{PQ + RS}}$
- D
$\sqrt {\frac{{P{Q^2} + R{S^2}}}{2}} $
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