The abscissa of the points of the curve $y = {x^3}$ in the interval $ [-2, 2]$, where the slope of the tangents can be obtained by mean value theorem for the interval $[-2, 2], $ are
$ \pm {2 \over {\sqrt 3 }}$
$ \pm \sqrt 3 $
$ \pm {{\sqrt 3 } \over 2}$
$0$
A value of $c$ for which the conclusion of mean value the theorem holds for the function $f(x) = log{_e}x$ on the interval $[1, 3]$ is
Let $f(x) = (x-4)(x-5)(x-6)(x-7)$ then -
In the mean value theorem, $f(b) - f(a) = (b - a)f'(c)$if $a = 4$, $b = 9$ and $f(x) = \sqrt x $ then the value of $c$ is
The function $f(x) = {(x - 3)^2}$ satisfies all the conditions of mean value theorem in $[3, 4].$ A point on $y = {(x - 3)^2}$, where the tangent is parallel to the chord joining $ (3, 0)$ and $(4, 1)$ is
Which of the following function can satisfy Rolle's theorem ?