Let v_1 = variance of {13, 1 6, 1 9, . . . . | vedclass

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Question

$ \mathrm{v}_{1}= 	ext { variance of }\{13,16,19, \ldots \ldots, 103\} $

$= 	ext { variance of }\{3,6,9, \ldots \ldots, 93\} $

$= 9(	ext { va

Vedclass · Accepted Answer

$1 : 4$

Vedclass · Answer

$ \mathrm{v}_{1}= 	ext { variance of }\{13,16,19, \ldots \ldots, 103\} $

$= 	ext { variance of }\{3,6,9, \ldots \ldots, 93\} $

$= 9(	ext { variance of }\{1,2,3, \ldots .31\}) $

${v_2} = {m{variance of }}\{ 20,26,32, \ldots .,200\} $

$ = {m{ variance of }}\{ 6,12,18, \ldots .,186\} $

$=36 	ext { (variance of }\{1,2,3, \ldots . .31\}) $

$ 	herefore  \frac{\mathrm{v}_{1}}{\mathrm{v}_{2}}=\frac{1}{4} $

Class	$10-20$	$20-30$	$30-40$
Frequency	$2$	$x$	$2$

Let $v_1 =$ variance of $\{13, 1 6, 1 9, . . . . . , 103\}$ and $v_2 =$ variance of $\{20, 26, 32, . . . . . , 200\}$, then $v_1 : v_2$ is

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