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13.Statistics
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જો $v_1 =$ $\{13, 1 6, 1 9, . . . . . , 103\}$ નો વિચરણ અને $v_2 =$ $\{20, 26, 32, . . . . . , 200\}$ નો વિચરણ હોય તો $v_1 : v_2$ મેળવો.
A
$1 : 2$
B
$1 : 1$
C
$4 : 9$
D
$1 : 4$
Solution
$ \mathrm{v}_{1}= \text { variance of }\{13,16,19, \ldots \ldots, 103\} $
$= \text { variance of }\{3,6,9, \ldots \ldots, 93\} $
$= 9(\text { variance of }\{1,2,3, \ldots .31\}) $
${v_2} = {\rm{variance of }}\{ 20,26,32, \ldots .,200\} $
$ = {\rm{ variance of }}\{ 6,12,18, \ldots .,186\} $
$=36 \text { (variance of }\{1,2,3, \ldots . .31\}) $
$ \therefore \frac{\mathrm{v}_{1}}{\mathrm{v}_{2}}=\frac{1}{4} $
Standard 11
Mathematics
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આવુતિ વિતરણ
| $X$ | $c$ | $2c$ | $3c$ | $4c$ | $5c$ | $6c$ |
| $f$ | $2$ | $1$ | $1$ | $1$ | $1$ | $1$ |
નુંવિચરણ જો $160$ હોય તો $\mathrm{c} \in \mathrm{N}$ નું મૂલ્ય ………… છે.
