13.Statistics
normal

જો $v_1 =$ $\{13, 1 6, 1 9, . . . . . , 103\}$ નો વિચરણ અને $v_2 =$ $\{20, 26, 32, . . . . . , 200\}$ નો વિચરણ હોય તો $v_1 : v_2$ મેળવો. 

A

$1 : 2$

B

$1 : 1$

C

$4 : 9$

D

$1 : 4$

Solution

$ \mathrm{v}_{1}= \text { variance of }\{13,16,19, \ldots \ldots, 103\} $ 

$= \text { variance of }\{3,6,9, \ldots \ldots, 93\} $

$= 9(\text { variance of }\{1,2,3, \ldots .31\}) $ 

${v_2} = {\rm{variance of }}\{ 20,26,32, \ldots .,200\} $

$ = {\rm{ variance of }}\{ 6,12,18, \ldots .,186\} $

$=36 \text { (variance of }\{1,2,3, \ldots . .31\}) $ 

$ \therefore  \frac{\mathrm{v}_{1}}{\mathrm{v}_{2}}=\frac{1}{4} $

Standard 11
Mathematics

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