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Which of the following Boolean expressions is not a tautology ?
$(\sim \mathrm{p} \Rightarrow \mathrm{q}) \vee(\sim \mathrm{q} \Rightarrow p)$
$(\mathrm{q} \Rightarrow p) \vee(\sim \mathrm{q} \Rightarrow p)$
$(\mathrm{p} \Rightarrow \mathrm{q}) \vee(\sim \mathrm{q} \Rightarrow p)$
$(\mathrm{p} \Rightarrow \sim \mathrm{q}) \vee(\sim \mathrm{q} \Rightarrow p)$
Solution
$(1)(\sim p \rightarrow q) \vee(\sim q \rightarrow p)$
$=(p \vee q) \vee(q \vee p)$
$=(p \vee p) \vee(q \vee q)$
$= \mathrm{p} \vee \mathrm{q}$
Which is not a tautology.
$(2)(q \rightarrow p) \vee(\sim q \rightarrow p)$
$=(\sim q \vee p) \vee(q \vee p)$
$=(\sim q \vee q) \vee p$
$= t \vee p=t$
$(3)(p \rightarrow q) \vee(\sim q \rightarrow p)$
$=(\sim p \vee q) \vee(q \vee p)$
$=(\sim p \vee p) \vee q$
$= t \vee q=t$
$(4)(p \rightarrow \sim q) \vee(\sim q \rightarrow p)$
$=(\sim p \vee \sim q) \vee(q \vee p)$
$=(\sim p \vee q) \vee(\sim q \vee q)$
$= t \vee t=t$