Which of the following Boolean expressions is not a tautology ?
$(\sim \mathrm{p} \Rightarrow \mathrm{q}) \vee(\sim \mathrm{q} \Rightarrow p)$
$(\mathrm{q} \Rightarrow p) \vee(\sim \mathrm{q} \Rightarrow p)$
$(\mathrm{p} \Rightarrow \mathrm{q}) \vee(\sim \mathrm{q} \Rightarrow p)$
$(\mathrm{p} \Rightarrow \sim \mathrm{q}) \vee(\sim \mathrm{q} \Rightarrow p)$
The negation of the compound proposition $p \vee (\sim p \vee q)$ is
If $\left( {p \wedge \sim q} \right) \wedge \left( {p \wedge r} \right) \to \sim p \vee q$ is false, then the truth values of $p, q$ and $r$ are respectively
Negation of $p \wedge (\sim q \vee \sim r)$ is -
The converse of the statement $((\sim p) \wedge q) \Rightarrow r$ is
Statement $-1$ : The statement $A \to (B \to A)$ is equivalent to $A \to \left( {A \vee B} \right)$.
Statement $-2$ : The statement $ \sim \left[ {\left( {A \wedge B} \right) \to \left( { \sim A \vee B} \right)} \right]$ is a Tautology