Twelve tickets are numbered 1 to 12 . One ticket is drawn at random, then probability of number to b

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14.Probability

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Twelve tickets are numbered $1$ to $12$. One ticket is drawn at random, then the probability of the number to be divisible by $2$ or $3$, is

A

$\frac{2}{3}$

B

$\frac{7}{{12}}$

C

$\frac{5}{6}$

D

$\frac{3}{4}$

Solution

(a) $P(2 \cup 3) = P(2) + P(3) – P(2 \cap 3)$

$ = \frac{6}{{12}} + \frac{4}{{12}} – \frac{2}{{12}} = \frac{2}{3}.$

Standard 11

Mathematics

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