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14.Probability
easy
Twelve tickets are numbered $1$ to $12$. One ticket is drawn at random, then the probability of the number to be divisible by $2$ or $3$, is
A
$\frac{2}{3}$
B
$\frac{7}{{12}}$
C
$\frac{5}{6}$
D
$\frac{3}{4}$
Solution
(a) $P(2 \cup 3) = P(2) + P(3) – P(2 \cap 3)$
$ = \frac{6}{{12}} + \frac{4}{{12}} – \frac{2}{{12}} = \frac{2}{3}.$
Standard 11
Mathematics
Similar Questions
Fill in the blanks in following table :
$P(A)$ | $P(B)$ | $P(A \cap B)$ | $P (A \cup B)$ |
$0.5$ | $0.35$ | ……… | $0.7$ |
easy