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8. Introduction to Trigonometry
hard
સાબિત કરો કે, $\sec A(1-\sin A)(\sec A+\tan A)=1$
Option A
Option B
Option C
Option D
Solution
ડા.બા. $=\sec A (1-\sin A )(\sec A +\tan A )$
$=\left(\frac{1}{\cos A }\right)(1-\sin A )\left(\frac{1}{\cos A }+\frac{\sin A }{\cos A }\right)$
$=\frac{(1-\sin A)(1+\sin A)}{\cos ^{2} A}=\frac{1-\sin ^{2} A}{\cos ^{2} A}$
$=\frac{\cos ^{2} A}{\cos ^{2} A}=1=$ જ.બા.
Standard 10
Mathematics