Suppose that A, B, C are events such that P,(A) = P,(B) = P,(C) = frac{1}{4},,P,(AB) = P,(CB) = 0,,P

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14.Probability

easy

Suppose that $A, B, C$ are events such that $P\,(A) = P\,(B) = P\,(C) = \frac{1}{4},\,P\,(AB) = P\,(CB) = 0,\,P\,(AC) = \frac{1}{8},$ then $P\,(A + B) = $

A

$0.125$

B

$0.25$

C

$0.375$

D

$0.5$

Solution

(d) $P(A + B) = P(A) + P(B) – P(AB)$

$ = \frac{1}{4} + \frac{1}{4} – 0 = \frac{1}{2}.$

Standard 11

Mathematics

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