The {20^{th}} term of the series 2 times 4 + | vedclass

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Question

(b) The given series $2 	imes 4 + 4 	imes 6 + 6 	imes 8....$

${n^{th}}$ terms${T_n} = 2n\;.\;2(n + 1) = 4n(n + 1)$

Putting $n = 20$,

we ge

Vedclass · Accepted Answer

$1680$

Vedclass · Answer

(b) The given series $2 	imes 4 + 4 	imes 6 + 6 	imes 8....$

${n^{th}}$ terms${T_n} = 2n\;.\;2(n + 1) = 4n(n + 1)$

Putting $n = 20$,

we get ${T_{20}} = 4\;.\;20(20 + 1) = 1680$.

The ${20^{th}}$ term of the series $2 \times 4 + 4 \times 6 + 6 \times 8 + .......$ will be

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