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8. Sequences and Series
easy
The ${20^{th}}$ term of the series $2 \times 4 + 4 \times 6 + 6 \times 8 + .......$ will be
A
$1600$
B
$1680$
C
$420$
D
$840$
Solution
(b) The given series $2 \times 4 + 4 \times 6 + 6 \times 8….$
${n^{th}}$ terms${T_n} = 2n\;.\;2(n + 1) = 4n(n + 1)$
Putting $n = 20$,
we get ${T_{20}} = 4\;.\;20(20 + 1) = 1680$.
Standard 11
Mathematics