અભિવ્યક્તિ $(5+x)^{500}+x(5+x)^{499}+x^{2}(5+x)^{498}+\ldots . x^{500}$ $x>0$ માં $x ^{101}$ નો સહુગુણક ......... છે.
${ }^{501} C _{101}(5)^{399}$
${ }^{501} C _{101}(5)^{400}$
${ }^{501} C _{100}(5)^{400}$
${ }^{500} C _{101}(5)^{399}$
$2.{}^{20}{C_0} + 5.{}^{20}{C_1} + 8.{}^{20}{C_2} + 11.{}^{20}{C_3} + ......62.{}^{20}{C_{20}}$ =
જો $\sum\limits_{K = 1}^{12} {12K{.^{12}}{C_K}{.^{11}}{C_{K - 1}}} $ ની કિમત $\frac{{12 \times 21 \times 19 \times 17 \times ........ \times 3}}{{11!}} \times {2^{12}} \times p$ હોય તો $p$ ની કિમત મેળવો
$\left( \begin{array}{l}30\\0\end{array} \right)\,\left( \begin{array}{l}30\\10\end{array} \right) - \left( \begin{array}{l}30\\1\end{array} \right)\,\left( \begin{array}{l}30\\11\end{array} \right)$ + $\left( \begin{array}{l}30\\2\end{array} \right)\,\left( \begin{array}{l}30\\12\end{array} \right) + ....... + \left( \begin{array}{l}30\\20\end{array} \right)\,\left( \begin{array}{l}30\\30\end{array} \right) = .$ . ..
$\sum_{\mathrm{k}=0}^{20}\left({ }^{20} \mathrm{C}_{\mathrm{k}}\right)^{2}$ ની કિમંત મેળવો.
$(x-1) (x- 2) (x-3)...............(x-10)$ ના વિસ્તરણમાં $x^8$ નો સહગુણક મેળવો