- Home
- Standard 11
- Mathematics
7.Binomial Theorem
normal
$(1-x)^{30} \, (1 + x + x^2)^{29}$ ના વિસ્તરણમાં $x^{37}$ નો સહગુણક મેળવો
A
$0$
B
${}^{29}{C_{12}}$
C
$ - {}^{29}{C_{12}}$
D
એક પણ નહી
Solution
$(1-x)^{30}\left(1+x+x^{2}\right)^{29}$
$(1-x)\left(1-x^{3}\right)^{29}$
$\left(1-x^{3}\right)^{29}-x\left(1-x^{3}\right)^{29} \longrightarrow$ Coeff of $x^{37}$
$\mathrm{O}-^{29} \mathrm{C}_{12}(-1)^{12} \Rightarrow-^{29} \mathrm{C}_{12}$
Standard 11
Mathematics
