7.Binomial Theorem
easy

જો ${(1 + x)^{21}}$ ના વિસ્તરણમાં ${x^r}$ અને ${x^{r + 1}}$ ના સહગુણક સમાન હોય તો $ r$ મેળવો.

A

$9$

B

$10$

C

$11$

D

$12$

Solution

(b) ${T_{r + 1}} = {\,^{21}}{C_r}{(1)^{21 – r}}{(x)^r} = {\,^{21}}{C_r}$

$\therefore $Coefficient of ${x^r} = {\,^{21}}{C_r}$ and coefficient of ${x^{r + 1}} = {\,^{21}}{C_{r + 1}}$

So, we must have $^{21}{C_r} = {\,^{21}}{C_{r + 1}} \Rightarrow r = 10$.

Standard 11
Mathematics

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