Gujarati
4-2.Quadratic Equations and Inequations
easy

The complete solution of the inequation ${x^2} - 4x < 12\,{\rm{ is}}$

A

$x < - \,2$ or $x > 6$

B

$ - \,6 < x < 2$

C

$2 < x < 6$

D

$ - \,2 < x < 6$

Solution

(d) ${x^2} – 4x < 12$

==> ${x^2} – 4x – 12 < 0$ ==> ${x^2} – 6x + 2x – 12 < 0$

==> $(x – 6)(x + 2) < 0$ ==> $ – 2 < x < 6$.

Standard 11
Mathematics

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