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4-2.Quadratic Equations and Inequations
easy
The complete solution of the inequation ${x^2} - 4x < 12\,{\rm{ is}}$
A
$x < - \,2$ or $x > 6$
B
$ - \,6 < x < 2$
C
$2 < x < 6$
D
$ - \,2 < x < 6$
Solution
(d) ${x^2} – 4x < 12$
==> ${x^2} – 4x – 12 < 0$ ==> ${x^2} – 6x + 2x – 12 < 0$
==> $(x – 6)(x + 2) < 0$ ==> $ – 2 < x < 6$.
Standard 11
Mathematics