The complete solution of the inequation ${x^2} - 4x < 12\,{\rm{ is}}$
$x < - \,2$ or $x > 6$
$ - \,6 < x < 2$
$2 < x < 6$
$ - \,2 < x < 6$
If $a, b, c, d$ are four distinct numbers chosen from the set $\{1,2,3, \ldots, 9\}$, then the minimum value of $\frac{a}{b}+\frac{c}{d}$ is
The roots of the equation ${x^4} - 4{x^3} + 6{x^2} - 4x + 1 = 0$ are
The locus of the point $P=(a, b)$ where $a, b$ are real numbers such that the roots of $x^3+a x^2+b x+a=0$ are in arithmetic progression is
Consider the following two statements
$I$. Any pair of consistent liner equations in two variables must have a unique solution.
$II$. There do not exist two consecutive integers, the sum of whose squares is $365$.Then,
The number of real solutions of the equation $|x{|^2}$-$3|x| + 2 = 0$ are