Smallest value of {x^2} - 3x + 3 in interval (

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4-2.Quadratic Equations and Inequations

easy

The smallest value of ${x^2} - 3x + 3$ in the interval $( - 3,\,3/2)$ is

$3/4$

$5$

$-15$

$-20$

Solution

(a) ${x^2} – 3x + 3 = {\left( {x – \frac{3}{2}} \right)^2} + \frac{3}{4}$
Therefore, smallest value is $\frac{3}{4}$, which lie in $\left( { – 3,\frac{3}{2}} \right)$

Standard 11

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medium

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Solution

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