The smallest value of {x^2} - 3x + 3 in the i | vedclass

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Question

(a) ${x^2} - 3x + 3 = {\left( {x - \frac{3}{2}} \right)^2} + \frac{3}{4}$
Therefore, smallest value is $\frac{3}{4}$, which lie in $\left( { - 3,\fra

Vedclass · Accepted Answer

$3/4$

Vedclass · Answer

(a) ${x^2} - 3x + 3 = {\left( {x - \frac{3}{2}} \right)^2} + \frac{3}{4}$
Therefore, smallest value is $\frac{3}{4}$, which lie in $\left( { - 3,\frac{3}{2}} \right)$

The smallest value of ${x^2} - 3x + 3$ in the interval $( - 3,\,3/2)$ is

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