The density of a material in SI, units is 128 | vedclass

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Question

$\begin{array}{l}
\frac{{128kg}}{{{m^3}}} = \frac{{125\left( {50g} \right)\left( {20} \right)}}{{{{\left( {25cm} \right)}^3}{{\left( 4 \right)}^3}}}\

Vedclass · Accepted Answer

$40$

Vedclass · Answer

$\begin{array}{l}
\frac{{128kg}}{{{m^3}}} = \frac{{125\left( {50g} ight)\left( {20} ight)}}{{{{\left( {25cm} ight)}^3}{{\left( 4 ight)}^3}}}\
 = \frac{{128}}{{64}}\left( {20} ight)units\
 = 40units
\end{array}$

The density of a material in $SI\, units$ is $128\, kg\, m^{-3}$. In certain units in which the unit of length is $25\, cm$ and the unit of mass $50\, g$, the numerical value of density of the material is

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