The equation of the normal at the point $(6, 4)$ on the hyperbola $\frac{{{x^2}}}{9} - \frac{{{y^2}}}{{16}} = 3$, is

  • A

    $3x + 8y = 50$

  • B

    $3x - 8y = 50$

  • C

    $8x + 3y = 50$

  • D

    $8x - 3y = 50$

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