Equation sin x + sin y + sin z = - 3 for 0 le x le 2π , 0 le y le 2π , 0 le z le 2π , has

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Trigonometrical Equations

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The equation $\sin x + \sin y + \sin z = - 3$ for $0 \le x \le 2\pi ,$ $0 \le y \le 2\pi ,$ $0 \le z \le 2\pi $, has

A

One solution

B

Two sets of solutions

C

Four sets of solutions

D

No solution

Solution

(a) Given $\sin x + \sin y + \sin z = – 3$ is satisfied only when

$x = y = z = \frac{{3\pi }}{2},$ for $x,\,y,\,z \in [0,\,\,2\pi ].$

Standard 11

Mathematics

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