Gujarati
10-1.Circle and System of Circles
easy

वृत्तों ${x^2} + {y^2} + x - y + 2 = 0$ व $3{x^2} + 3{y^2} - 4x - 12 = 0$ के मूलाक्ष का समीकरण है

A

$2{x^2} + 2{y^2} - 5x + y - 14 = 0$

B

$7x - 3y + 18 = 0$

C

$5x - y + 14 = 0$

D

इनमें से कोई नहीं

Solution

(b) मूलाक्ष का समीकरण ${S_1} – {S_2} = 0$ होता है।

${S_1} \equiv {x^2} + {y^2} + x – y + 2 = 0$

${S_2} = {x^2} + {y^2} – \frac{4}{3}x – 4 = 0$

$ \Rightarrow {S_1} – {S_2} = \frac{7}{3}x – y + 6 = 0$

व $7x – 3y + 18 = 0$.

Standard 11
Mathematics

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