Gujarati
10-1.Circle and System of Circles
easy

The equation of the normal to the circle ${x^2} + {y^2} - 2x = 0$ parallel to the line $x + 2y = 3$ is

A

$2x + y - 1 = 0$

B

$2x + y + 1 = 0$

C

$x + 2y - 1 = 0$

D

$x + 2y + 1 = 0$

Solution

(c) Any line parallel to $x + 2y = 3$ is $x + 2y + \lambda = 0$

and for this to be a normal to the given circle, must pass through its centre $(1, 0)$,

$i.e$. $\lambda = – 1$.

So, normal is $x + 2y – 1 = 0$.

Standard 11
Mathematics

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