Gujarati
10-2. Parabola, Ellipse, Hyperbola
easy

अतिपरवलय $2{x^2} - 3{y^2} = 6$ की स्पर्श रेखा जो रेखा $y = 3x + 4$ के समान्तर है, होगी

A

$y = 3x + 5$

B

$y = 3x - 5$

C

$y = 3x + 5$ और $y = 3x - 5$

D

इनमें से कोई नहीं

Solution

(c) माना स्पर्श  $y = 3x + c$

$c =  \pm \sqrt {{a^2}{m^2} – {b^2}}  =  \pm \sqrt {3.9 – 2}  =  \pm 5$

$y = 3x \pm 5$.

Standard 11
Mathematics

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