The equation of the tangents to the conic $3{x^2} - {y^2} = 3$ perpendicular to the line $x + 3y = 2$ is
The equation of the tangents to the conic $3{x^2} - {y^2} = 3$ perpendicular to the line $x + 3y = 2$ is
- A
$y = 3x \pm \sqrt 6 $
- B
$y = 6x \pm \sqrt 3 $
- C
$y = x \pm \sqrt 6 $
- D
$y = 3x \pm 6$
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- [JEE MAIN 2023]
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