2sqrt 3 cos theta = tan theta का व्याप | vedclass

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Question

$2\sqrt 3 {\cos ^2}	heta  = \sin 	heta $

$\Rightarrow$  $2\sqrt 3 {\sin ^2}	heta  + \sin 	heta  - 2\sqrt 3  = 0$

$\

Vedclass · Accepted Answer

$n\pi + {( - 1)^n}\frac{\pi }{3}$

Vedclass · Answer

$2\sqrt 3 {\cos ^2}	heta  = \sin 	heta $

$\Rightarrow$  $2\sqrt 3 {\sin ^2}	heta  + \sin 	heta  - 2\sqrt 3  = 0$

$\Rightarrow$ $\sin 	heta  = \frac{{ - 1 \pm 7}}{{4\sqrt 3 }} $

$\Rightarrow \sin 	heta  = \frac{{ - 8}}{{4\sqrt 3 }}{m{,}}$ (असंभव)

तथा $\sin 	heta  = \frac{6}{{4\sqrt 3 }} = \frac{{\sqrt 3 }}{2}$

$\Rightarrow$ $	heta  = n\pi  + {( - 1)^n}\frac{\pi }{3}$.

$2\sqrt 3 \cos \theta = \tan \theta $ का व्यापक मान होगा

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