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Trigonometrical Equations
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यदि $\tan \theta = - \frac{1}{{\sqrt 3 }}$ व $\sin \theta = \frac{1}{2}$, $\cos \theta = - \frac{{\sqrt 3 }}{2}$, तो $\theta $ का मुख्य मान होगा
A
$\frac{\pi }{6}$
B
$\frac{{5\pi }}{6}$
C
$\frac{{7\pi }}{6}$
D
$ - \frac{\pi }{6}$
Solution
(b) $\tan \theta = \frac{{ – 1}}{{\sqrt 3 }} = \tan \left( {\pi – \frac{\pi }{6}} \right)$,
$\sin \theta = \frac{1}{2} = \sin \left( {\pi – \frac{\pi }{6}} \right)$
तथा $\cos \theta = \frac{{ – \sqrt 3 }}{2} = \cos \left( {\pi – \frac{\pi }{6}} \right)$
अत:, $\theta$ का मुख्य मान $= \frac{{5\pi }}{6}$.
Standard 11
Mathematics
