The half-life of a radioactive element A is t | vedclass

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Question

${\left( {{{	ext{T}}_{1/2}}} ight)_{	ext{A}}} = {\left( {{{	ext{t}}_{{	ext{mean}}}}} ight)_{	ext{B}}}$

$ \Rightarrow \frac{{0.693}}{{{\lam

Vedclass · Accepted Answer

$B$ will decay at a faster rate than $A$

Vedclass · Answer

${\left( {{{	ext{T}}_{1/2}}} ight)_{	ext{A}}} = {\left( {{{	ext{t}}_{{	ext{mean}}}}} ight)_{	ext{B}}}$

$ \Rightarrow \frac{{0.693}}{{{\lambda _A}}} = \frac{1}{{{\lambda _B}}}$ $ \Rightarrow {\lambda _A} = 0.693{\lambda _B}$

or $\quad \lambda_{A} < \lambda_{B}$

Also rate of decay $=\lambda \mathrm{N}$

Initially number of atoms $(N)$ of both are

equal but since $\lambda_{\mathrm{B}}>\lambda_{\mathrm{A}},$ therefore Bwill decay at a faster rate than $\mathrm{A}$

The half-life of a radioactive element $A$ is the same as the mean-life of another radioactive element $B.$ Initially both substances have the same number of atoms, then

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