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13.Nuclei
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રેડિયો એક્ટિવ તત્વનો અર્ધઆયુ $1.2 \times 10^7\, s$ છે. તો $4.0 \times 10^{15}$ પરમાણુ નો વિભંજન દર.
A
$4.6 \times {10^{12}}\,atoms/s$
B
$2.3 \times {10^{11}}\,atoms/s$
C
$4.6 \times {10^{10}}\,atoms/s$
D
$2.3 \times {10^{8}}\,atoms/s$
(AIIMS-2010)
Solution
We have, $\frac{\mathrm{dN}}{\mathrm{dt}}=\lambda \mathrm{N}$
$\lambda=\frac{0.693}{\mathrm{T}}=\frac{0.693}{1.2 \times 10^{7}}$
$\frac{\mathrm{d} \mathrm{N}}{\mathrm{dt}}=\frac{0.693}{1.2 \times 10^{7}} \times 4 \times 10^{15}$
$=2.3 \times 10^{8} \mathrm{\,atom} / \mathrm{s}$
Standard 12
Physics
