13.Nuclei
medium

The half life of a radioactive substance is $20$ minutes. In $........\,minutes$ time,the activity of substance drops to $\left(\frac{1}{16}\right)^{ th }$ of its initial value.

A

$80$

B

$20$

C

$40$

D

$60$

(NEET-2023)

Solution

Half life $T=20 min$

Left fraction of activity $\frac{1}{16}$

$\because \frac{ R }{ R _0} =\left(\frac{1}{2}\right)^{ t / T }$

$\frac{1}{16} =\left(\frac{1}{2}\right)^{ t / 20}$

$\left(\frac{1}{2}\right)^4 =\left(\frac{1}{2}\right)^{ t / 20}$

$4 =\frac{ t }{20}$

$t =80\,min$

Standard 12
Physics

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