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13.Nuclei
medium
The half life of a radioactive substance is $20$ minutes. In $........\,minutes$ time,the activity of substance drops to $\left(\frac{1}{16}\right)^{ th }$ of its initial value.
A
$80$
B
$20$
C
$40$
D
$60$
(NEET-2023)
Solution
Half life $T=20 min$
Left fraction of activity $\frac{1}{16}$
$\because \frac{ R }{ R _0} =\left(\frac{1}{2}\right)^{ t / T }$
$\frac{1}{16} =\left(\frac{1}{2}\right)^{ t / 20}$
$\left(\frac{1}{2}\right)^4 =\left(\frac{1}{2}\right)^{ t / 20}$
$4 =\frac{ t }{20}$
$t =80\,min$
Standard 12
Physics