13.Nuclei
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એક રેડિયો એક્ટિવ તત્વનો અર્ધઆયુ $20\; min$ છે. જો $t _{1}=\frac{1}{3}$ પદાર્થનું વિભંજન થતાં લાગતો સમય, $t_{2}=\frac{2}{3}$ પદાર્થનું વિભંજન થતાં લાગતો સમય હોય, તો $t_{2}-t_{1}$ ............. મીનીટ થાય.

A

$14$ 

B

$20$ 

C

$28 $ 

D

$7 $ 

(AIEEE-2011)

Solution

Number of undecayed atom after time $t_{2};$

$\frac{N_{0}}{3}=N_{0} e^{-\lambda t_{2}}$      …. $(i)$

Number of undecayed atom after time $t_{1};$

$\frac{2 N_{0}}{3}=N_{0} e^{-\lambda t_{1}}$   …. $(ii)$

From $(i)$, $e^{-\lambda t_{2}}=\frac{1}{3}$

$\Rightarrow \quad-\lambda t_{2}=\log _{e}\left(\frac{1}{3}\right)$   …. $(iii)$

From $(ii)$ $-e^{-\lambda t_{2}}=\frac{2}{3}$

$\Rightarrow \quad-\lambda t_{1}=\log _{\mathrm{e}}\left(\frac{2}{3}\right)$   …. $(iv)$

Solving $(iii)$ and $(iv)$, we get $t_{2}-t_{1}=20 \mathrm{\,min}$

Standard 12
Physics

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