13.Nuclei
medium

रेडियम का अर्द्ध-आयुकाल $1600$ वर्ष है, तो $6400$ वर्षों पश्चात् रेडियम का शेष अंश बचेगा

A

$\frac{1}{4}$

B

$\frac{1}{2}$

C

$\frac{1}{8}$

D

$\frac{1}{{16}}$

(AIPMT-1991)

Solution

भाग $ = \frac{N}{{{N_0}}} = {\left( {\frac{1}{2}} \right)^{\frac{{6400}}{{1600}}}} = {\left( {\frac{1}{2}} \right)^4} = \frac{1}{{16}}$

Standard 12
Physics

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