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3-1.Vectors
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The magnitude of vector $\overrightarrow A ,\,\overrightarrow B $ and $\overrightarrow C $ are respectively $12, 5$ and $13$ units and $\overrightarrow A + \overrightarrow B = \overrightarrow C $ then the angle between $\overrightarrow A $ and $\overrightarrow B $ is
A
$0$
B
$\pi $
C
$\pi /2$
D
$\pi /4$
Solution

(c) $C = \sqrt {{A^2} + {B^2}} $
The angle between $A$ and $B$ is $\frac{\pi }{2}$
Standard 11
Physics