The mean and the variance of five observation | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

Mean $\bar x = 4,{\sigma ^2} = 5.2,n = 5,{x_1} = 3,{x_2} = 4 = {x_3}$

$\sum {{x_i} = 20} $

${x_4} + {x_5} = 9\,\,\,\,\,\,\,........\left( i

Vedclass · Accepted Answer

$7$

Vedclass · Answer

Mean $\bar x = 4,{\sigma ^2} = 5.2,n = 5,{x_1} = 3,{x_2} = 4 = {x_3}$

$\sum {{x_i} = 20} $

${x_4} + {x_5} = 9\,\,\,\,\,\,\,........\left( i \right)$

$\frac{{\sum {x_i^2} }}{x} - {\left( {\bar x} \right)^2} = {\sigma ^2} \Rightarrow \sum {x_i^2}  = 106$

$x_4^2 + x_5^2 = 65\,\,\,\,\,\,\,\,........\left( {ii} \right)$

Using $(i)$ and $(ii)$ ${\left( {{x_4} - {x_5}} \right)^2} = 49$

$\left| {{x_4} - {x_5}} \right| = 7$

The mean and the variance of five observations are $4$ and $5.20,$ respectively. If three of the observations are $3, 4$ and $4;$ then the absolute value of the difference of the other two observations, is

Similar Questions

If the mean deviation about the mean of the numbers $1,2,3, \ldots ., n$, where $n$ is odd, is $\frac{5(n+1)}{n}$, then $n$ is equal to

The mean and variance of $8$ observations are $10$ and $13.5,$ respectively. If $6$ of these observations are $5,7,10,12,14,15,$ then the absolute difference of the remaining two observations is

For a frequency distribution, standard deviation is computed by

Find the mean and variance of the frequency distribution given below:

$\begin{array}{|l|l|l|l|l|} \hline x & 1 \leq x<3 & 3 \leq x<5 & 5 \leq x<7 & 7 \leq x<10 \\ \hline f & 6 & 4 & 5 & 1 \\ \hline \end{array}$